Question

a block of mass m moving with velocity v on a smooth horizontal surface hits the spring of constant k as shown.the max. compression in the spring is?
a)$\sqrt{2m/k}$.v
b)$\sqrt{m/k}$.v
c)$\sqrt{m/2k}$.v

Answer 1

the block has mass m
it is moving with kinetic energy 1/2mv²
it strikes the spring with speed v and comes to rest after moving distance x
so its kinetic energy must equal to spring Potential energy
$\frac{1}{2}mv^2= \frac{1}{2}kx^2 \\ x^2= \frac{m}{k}v^2 \\ x=v \sqrt{ \frac{m}{k} }$
so its option b)

Answer 2

Answer:

√m/k .v

Explanation:

option b is correct