a block of mass M with a semicircular track of radius R rests on a horizontal frictionless surface a uniform cylinder of radius r and mass m is released from rest from the top point the cylinder slips on the semicircular frictionless track the distance travelled by the block when the cylinder reaches the lower point is and also find the velocity of block when it ts at lower point
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Answer:
distance={m(R-r)}/(M+m)
velocity = m[√{2g(R-r)/M(m+M)}]
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Answer: X = m(R-r)/(M+m)
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