A block of material has a density rho_(1) and floats three-fourth submerged in a liquid of unknown density. Show tht the density rho_(2) of the unknown liquid is given by rho_(2)=(4)/(3)rho_(1).
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To prove : The density ρ₂ of the unknown liquid is given by ρ₂ = (4/3) ρ₁
Proof :
- Let us consider that,
m = mass
g = acceleration due to gravity
V = volume
σ = density
- As per the question, a block of material having density ρ₁ floats 3/4th submerged in a liquid of unknown density.
- Therefore, weight = upthrust
m g = V σ g
V ρ₁ g = ( 3 / 4 V ) ρ₂ g
ρ₂ = 4 / 3 ρ₁
- Hence, proved.
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