Question

In taking a solid ball of rubber from the surface to the bottom of a lake of 180 m depth, reduction in the volume of the ball is 0.01 %. The density of water of the lake is 1xx10^(3) kg//m^(3). Determine the value of the bulk modulus of elasticity of rubber . (g = 9.8 m//s^(2))

Answer 1

The value of bulk modulus is B = 1.76 x 10^9 N/m

Explanation:

Height "h" = 180 m

ρ = 1000 Kg/ m^3

g = 9.8 m/s^2

ΔV/V x 100 = 0.01

B = ?

B =  ΔP ÷ ΔV/V  = ρgh / 0.01

B = 1 x 10^3 x 9.8 x 180 / 0.01 ÷ 100

B = 1.76 x 10^9 N/m

Thus the value of bulk modulus is B = 1.76 x 10^9 N/m