Question

A block of size 20m×10m×5 exerts a force of 30 N calculate the maximum & minimum pressure excerted by block on ground

Answer 1

⇒A₁ = (20×10)= 200 sq m.
⇒A₂ = (10×5) = 50 sq m.
⇒A₃ = (20×5) = 100 sq m.
∴A₁ is maximum and A₂ is minimum.
∴Minimum pressure P₁ = F/A₁ = 30/200 = 0.15 Nm⁻².
∴Maximum pressure P₂ = F/A₂ = 30/50 = 0.6 Nm⁻

Answer 2

$\large{\boxed{\red{\textbf{ Thanks\:For\:Ansking}}}}$

We know, when force is constant, pressure ∞ 1/Area.Therefore, pressure is maximum when area is minimum and vice versa.

By calculating the area of three faces, we get,

⇒A₁ = (20×10)= 200 sq m.

⇒A₂ = (10×5) = 50 sq m.

⇒A₃ = (20×5) = 100 sq m.

∴ A₁ is maximum and A₂ is minimum.

∴ Minimum pressure P₁ = F/A₁ = 30/200 = 0.15 Nm⁻².

∴ Maximum pressure P₂ = F/A₂ = 30/50 = 0.6 Nm⁻². (Ans)