Question

A block of size 20m×10m×5m exerts a force of 30N.Calculate the maximum and minimum pressure exerted by the block on ground?

Answer 1

As per the question , force exerted by block is 30 N. The dimensions of the block 20 m × 10 m × 5 m.

To find:

Maximum and Minimum Pressure exerted on the ground

Concept:

For constant Force , we can say that Pressure is inversely proportional to the Area upon which the force acts .

$Pressure \:\propto\: \: \dfrac{1}{Area}$

Calculation:

Maximum Pressure:

P1 = 30/(10×5) = 30/50 = 0.6 Pascal

Minimum Pressure :

P2 = 30/(20×10) = 30/200= 0.15 Pascal

Answer 2

Answer:

Explanation:

Given :-

Dimensions of the block = (20 × 10 × 5) m

Force exerted by block = 30 N

To Find :-

Maximum and Minimum pressure exerted by the block on ground.

Formula to be used :-

Pressure = Force/ Area

Solution :-

Putting all the values, we get

At first we will calculate area of three face,

A₁ = 20 × 10 = 200 m²

A₂ = 10 × 10 = 100 m²

A₃ = 5 × 10 = 50 m²

This shows, A₁ is maximum and A₂ is minimum pressure.

Minimum pressure, P₁ = F/A₁

⇒ Minimum pressure, P₁ = 30/200

⇒ Minimum pressure, P₁ = 0.15 Nm⁻².

Now, Maximum pressure.

Maximum pressure, P₂ = F/A₂

⇒ Maximum pressure, P₂ = 30/50

⇒ Maximum pressure, P₂ = 0.6 Nm⁻².

Hence,  the maximum and minimum pressure exerted by the block on ground 0.15 Nm⁻² and 0.6 Nm⁻².