Question

Calculate osmotic pressure of 0.25m solution of urea at 37degree celsius. r=0.0083 l bar/mol/k

Answer 1

Answer:

0.64325 bar

Explanation:

Since given concentration is too small

molarity ~molality

$\pi = crt$

= 0.25× 0.0083 ×310

=0.64325 bar

Answer 2

Answer:

6.43 bar.

Explanation:

π=CRT

T = 370C = 310 k

π=CRT =nvRT

=0.25×0.083×310

= 6.43 bar.

Since given concentration is too small

molarity ~molality

= 0.25× 0.0083 ×310

=0.64325 bar

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