Question

A block of size 30*10*20 cm^ 3 is lying on a tabletop find the pressure exerted by it if weight of the block is 30 N

Answer 1

Answer:

Given:1)size of block:30×20×10

2)force: 30N

To find: pressure = ?

solution: Pressure = Force/Area

=30/30×20×10

=1/200

=0.0005 N/m^2 or Pa

Answer 2

mass of the wooden block = m= 5 kgdimensions = 40 cm x 20 cm x 10 cm

the weight of the wooden block applies a thrust on the table top.That is,Thrust = F = mg=5 kg x 9.8 m/s2= 49 N

Area of a side = length x breadth

= 20 cm x 10 cm

= 200 cm?

= 0.02 m?

Pressure = thrust/ area

Pressure = 49 /o.02= 2450 N/m²

The same thrust in implied when it lies on the given dimension. Area= length x breadth= 40 x 20= 800= 0.08 m2