Physics, asked by dudduyashwanth2004, 6 months ago

A block of weight 100 N is lying on a rough horizontal surface. If coefficient of friction is 1/√3. The least possible force that can move the block is​

Answers

Answered by Ekaro
29

Answer :

Weight of block = 100N

Coefficient of friction = 1/√3

We have to find the least possible force that can move the block.

★ The least possible force that can move the block is maximum static friction force.

We know that, maximum static friction force is directly proportional to the normal reaction on body.

  • f ∝ N
  • f = μ × N = μ × mg

μ denotes coefficient of friction

mg denotes weight of body

⭆ f = μ × (mg)

ATQ, weight = mg = 100N

⭆ f = 1/√3 × 100

f 57.8N

Cheers!

Answered by Yeshwanth1245
0

Answer :

Weight of block = 100N

Coefficient of friction = 1/√3

We have to find the least possible force that can move the block

★ The least possible force that can move the block is maximum static friction force.

We know that, maximum static friction force is directly proportional to the normal reaction on body.

f ∝ N

f = μ × N = μ × mg

μ denotes coefficient of friction

mg denotes weight of body

⭆ f = μ × (mg)

ATQ, weight = mg = 100N

⭆ f = 1/√3 × 100

⭆ f ≥ 57.8N

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