Question

A block of weight 100 N is slowly moved up a smooth incline of inclination 37° by a person. Calculate the work done by the person in moving the block through a distance of 2 m, if the driving force is (a) parallel to the incline and (b) in the horizontal direction.

Answer 1

(a)The work done in the parallel slope is therefore 120 J.

(b)The work done horizontally is 120 J.

Explanation:

(a) Parallel to the slope:-  here the block gradually slides up,  

Parallel to the slope = resistant force of the weight part given :-

w = 100 N

θ = 37°

distance s = 2.0 m

Then driving force F = 100 × sin37° N

Work done = F × d

Work done = 100 × sin37° × 2.0  

Work done = 100 × 0.60 × 2.0  

Work done = 100 × 1.20  

Work done =120 J

The work done in the parallel slope is therefore 120 J.

(b) Force in the direction horizontal.  

If the driving force occurs in the horizontal direction, its part along the incline is equal to the force F of  

100 / sin37 ° N.

The work done = 120 J.  

That's why the work done horizontally is 120 J.

Answer 2

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