Physics, asked by hkruthika, 8 months ago

A block of weight 100N
and dimensions 50 cm x 30 cm x 10 cm rest on a table in 3 different positions with its base as a)50 cm x 30 cm
b)30 cm x 10 cm
c)50 cm x 10 cm
calculate pressure exerted in each case.

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Answers

Answered by saivenkatvanasarla
27

Answer:

HERE YOU GO .......

Explanation:

Given that,

the weight of the body = 100N= the force acting on surface

we know that pressure = force / area

1cm² = 10^-4m²

1N/m² = 1pascal = 1Pa

Case(1):

      area = 50x30= 1500cm² = 0.15m²

Pressure = force / area = 100÷0.15

Pressure = 666.67Pa

Case(2):

      area = 30x10 = 300cm² = 0.03m²

pressure = force / area = 100/0.03

pressure = 3333.33Pa

Case(3):

      area = 50x10 = 500cm² = 0.05m²

pressure = force/area = 100/0.05

pressure = 2000Pa

        HOPE IT HELPS YOU

Please mark it as the brainliest answer.

Answered by ace6608
2

Please mark me as brainliest..

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