Question

a block of weight 1N rests on an inclined plane of inclination theta with the horizontal. the coefficient of friction between the block and the inclined plane is mu. the minimum force that has to be applied parallel to the inclined plane to make body just move up the plane is

Answer 1

Answer:

The answer will be sintheta+mucostheta

Explanation:

According to the problem the weigh of the block is 1 N which making an angle of theta horizontally.

Therefore W = 1N

Now along with the inclined plane the weight component willbe = Wsintheta

Now as W =1 N therefore it will be sintheta

Now we know that if the block is going upward the friction force will be in downward direction

Therefore friction force ,f = muWcostheta[ where mu is the coefficient of friction]  Again as W = 1N therefore it will be mucostheta

Therefore the net force applied in the upward direction is sintheta +mucostheta

Answer 2

Answer:

here

Explanation:

refer to photo......