Question

a block of weight 5 Nand is pushed against a vertical wall by a force of 12 n the coefficient of friction between the wall and block is 0.6 magnitude of the force exerted by the wall on the block is​

Answer 1

Answer:

The force exerted by the wall on the block is​ 13 N

Explanation:

According to the problem the weight of the block is 5N, i.e mg= 5N

and the pushed force is 12n

Now the coefficient of friction between the wall and block is 0.6

now the let the friction is f

therefore, f= mg

                    f= 5N

Therefore the contact force= √12^2+5^2

                                                = 13

Answer 2

Explanation:

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