Question

a block of wood floats in brine solution of density 1.5g/cm³ such that three fifths of its volume is immersed into the brine solution calculate the density of wood​

Answer 1

Answer:

n a block of wood floats in brine solution of density 1.5g/cm³ such that three fifths of its volume is immersed

Explanation:

Answer 2

Answer:

density of the block  = 0.48 g/cm³

Explanation:

Given,

A block of wood floats in brine solution of density 1.15 g/cm^3 such that 3/5 th of its volume immersed into the brine.

To find: the density of wood.

Solution:

Let density of wood be ρ g/cm³ and volume be V cm³.

Weight of block of wood = Vρg = 980 Vρ cm/s²

Buoyancy force acting on the block = 3/5 * ( V * 0.8 * 980)

According to Archimedes Principle,

Weight of block = Buoyancy force acting on the block

i.e W = Fb

or, 980Vρ  = 3/5 * ( V * 0.8 * 980)

ρ  = 0.6 * 0.8= 0.48 g/cm³

Therefore, density of block = 0.48 g/cm³