A block of wood floats in water with 2/3 of its volume submerged calculate density of wood
Answers
Answered by
2
Explanation:
Let d be the density of wood,
the wood is submerged 4/5 of its volume, its weight is balanced by buoyant force of water on its 2/3 of volume.
by equilibrium of force
v*d*g = (2/3)*v*1.0*g (since density of water is 1 gm/cm^3)
d = 2/3 = 0.6667 gm/cm^3
Similar questions