A block of wood floats in water with 2/3 of its volume submerged.Its relative density is ?
Answers
Answered by
24
less dense will float in more dense liquid..
so, relative density of wood will be 2/3 = 0.667
hope am correct !!
so, relative density of wood will be 2/3 = 0.667
hope am correct !!
Answered by
33
Hi there,
====================
A block of wood floats in water with 2/3 of its volume submerged it means 1 / 3rd of it's volume is above in the water.
Let, V is the volume of the object.
and p
be its dencity. so, weight of the object , w = v
p
g
volume of water displaced = v - 1 / 3v = 2 / 3v
Dencity of the water = 1g/cc
weight of water displaced = ( 2/3v ) × 1× g
By, the law of flotation ,
weight of the object = weight of water displaced => v
p
g = 2 / 3 vg
=> p
= 2/3 g/cc
Thus ,the relative dencity of the object is:-
( 2/3 ) /1 = 2/3....i hope it helps
________________________________
====================
A block of wood floats in water with 2/3 of its volume submerged it means 1 / 3rd of it's volume is above in the water.
Let, V is the volume of the object.
and p
be its dencity. so, weight of the object , w = v
p
g
volume of water displaced = v - 1 / 3v = 2 / 3v
Dencity of the water = 1g/cc
weight of water displaced = ( 2/3v ) × 1× g
By, the law of flotation ,
weight of the object = weight of water displaced => v
p
g = 2 / 3 vg
=> p
= 2/3 g/cc
Thus ,the relative dencity of the object is:-
( 2/3 ) /1 = 2/3....i hope it helps
________________________________
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