a block of wood has a mass of 3.6 kg . Its volume is 0.0048 m^3. Find the volume of block below the water surface . Find the density of wood.
Answers
Answer:
We know that d=m/v
Mass of wood =3.6*1000=3600g
- d=3600/0.0048=36000000/48
The volume of wood below the water surface = 3.6 × 10^-3 m³.
The density of the block of wood is 750 kg/m³.
Given: A block of wood has a mass of 3.6 kg and its volume is 0.0048 m^3.
To Find: The volume of the block below the water surface.
The density of the wood.
Solution:
- We know that by the principle of Floatation,
Mass of an object = Mass of liquid displaced ....(1)
- The density of an object can be found using the formula,
Density = Mass / Volume .....(2)
Coming to the numerical, we have;
The mass of the block of wood = 3.6 kg
The volume of the block of wood = 0.0048 m^3
So, density of the block of wood = mass/volume = 3.6 / 0.0048 kg/m³
= 750 kg/m³
From (1), we can say that,
Mass of liquid displaced = Mass of wood
= 3.6 kg
Also, density of water = 1000 kg/m³
So, Volume of water displaced = mass of water displaced / Density of water
= 3.6 / 1000 m³
= 3.6 × 10^-3 m³
So, the volume of wood inside the water surface = 3.6 × 10^-3 m³.
Hence, the volume of wood below the water surface = 3.6 × 10^-3 m³.
The density of the block of wood is 750 kg/m³.
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