Question

Find the value of P so that
$( \frac{4}{5} ) {}^{3} \div ( \frac{4}{5} ) {}^{ - 3} equal \: to \: ( \frac{4}{5} ) {}^{3p}$
Class 8 question.​

Answer 1

Answer:

p=2

EXPLANATION:

if the bases are equal while dividing an expression then the powers are subtracted

Answer 2

Answer:-

${ (\frac{4}{5} )}^{3} \div {( \frac{4}{5} )}^{3} = {( \frac{4}{5}) }^{3p}$

${ (\frac{4}{5} )}^{3 - ( - 3)} = { (\frac{4}{5} )}^{3p}$

$( { \frac{4}{5} )}^{6} = ({ \frac{4}{5}) }^{3p}$

$6 = 3p$

$p = \frac{6}{3}$

$p = 2$

Done

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