A block of wood is kept on a table top. The mass of wooden block is 5 kg and its dimensions are 40 cm x 20 cm x 10 cm . Find the pressure exerted by the wooden block on the table top with its sides of dimensions
(a) 20cm x 10cm and (b) 40cm x 20cm
Answers
Answer:
Mass of wooden block= 5 kg
Dimensions of the block = (40 × 20 × 10) cm
Force exerted by the table top,
F = Weight of the block = mg= 5 × 9.8 = 49 N
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Answer:
The mass of the wooden block = 5 kg
The dimensions = 40 cm x 20 cm x 10 cm
Here, the weight of the wooden block applies a thrust on the table top.
That is,
Thrust = F (force) = m x g
= 5 kg x 9.8 m s^-2
= 49 N (newton)
Area of a side = length x breadth
= 20 cm x 10 cm
= 200 cm^2 = 0.02
From Eq. (10.20),
Pressure = 49 N / 0.02 m^2
= 2450 N m^-2.
When the block lies on its side of dimensions 40 cm x 20 cm, it exerts the same thrust.
Area = length x breadth
= 40 cm x 20 cm
= 800 cm^2 = 0.08 m^2
From Eq. (10.20),
Pressure = 49 N / 0.08 m^2
= 612.5 N m^-2
The pressure exerted by the side 20 cm x 10 cm is 2450 N m^-2 and by the side 40 cm x 20 cm is 612.5 N m^-2.