A block of wood of density 0.63 g/cm3, floats in a mixture of water and alcohol of density 0.91 g/cm3. What fraction of wood will be above the surface of the mixture?
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Answer:
9/13
Explanation:
The fraction of an object which will be above the surface is given a s the ratio of their densities.
0.63/0.91 = 63/91 = 9/13
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