Question

A block of wood of density 600kgm^-3 and volume 0.6 m^3 floats in water of density 1000 kg m^-3 .How much of it is below water level?​

Answer 1

$\frac{v \: in}{vtotal} \: = \: \frac{d \: solid}{d \: fluid}$

vin/0.6 = 600/1000

vin = 0.6×0.6

= 0.36 m³

vin is the volume of solid immersed

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Answer 2

Answer:

0.36m cube

Explanation:

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