Physics, asked by rupali4bharti, 3 months ago

one end of a rod of length l and mass m is hinged at a .it is released from rest from horizontal position ab as shown in fig. the force exerted by the rod on the hinge when it become vertical ​

Answers

Answered by nagathegenius
0

Explanation:

1/2*i*w^2=mgl/2

iw^2=mgl

w^2=mgl/I

w^2=mgl/ml^2/3

w=root 3g/l

velocity of centre of mass=l/2×w

v=l/2*root 3g/l

Force=mv^2/l

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