A block of wood of mass 6kg and dimensions 50 cm *30cm*20cm is placed on a table top.find the pressure exerted if the block lies on the table top with sides of dimensions.
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Answered by
2
P=F/A
F=mg = 6x9.8=58.8N
A=(50x30x20)/10^6=0.03m^2
P=58.8/0.03=1960N/m^2
F=mg = 6x9.8=58.8N
A=(50x30x20)/10^6=0.03m^2
P=58.8/0.03=1960N/m^2
Answered by
1
P=f/a
f=mg=6×9.8=58.8N
A=(50×30×20)/10^6=0.03m^²
p=58.8/0.03=1960Nm^²
f=mg=6×9.8=58.8N
A=(50×30×20)/10^6=0.03m^²
p=58.8/0.03=1960Nm^²
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