Question

A block of wood weighing 150 g is immersed in water( density of wood 0.8 g/cc). How much upward force doed yhe block experience?

Answer 1

The upward force or upthrust will be equal to the weight of the water displaced by submerged part of wood.

Answer 2

Given :

Mass of block , m = 150 g = 0.15 kg .

Density of wood , $\rho=0.8\ g/cm^3$ .

To Find :

How much upward force does the block experience .

Solution :

We know , the upward force will be equal to the weight of the water displaced by submerged part of wood .

Here , full block is submerged .

So , volume of wood is :

$V=\dfrac{M}{\rho}\\\\V=\dfrac{150\ g}{0.8\ g/cm^3}\\\\V=187.5\ cm^3$

Therefore , mass of water replaced is also 187.5 gm ( because its density is 1 g/cc ).

So , its weight is ,

$W=0.1875\times 10\ N\\\\W=1.875\ N$

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Fluids Mechanics

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