Question

The area of a triangle of base 35 is 420cmsquare. Find its altitude

Answer 1

$\frac{1}{2} \times b \times h = area \\ 420 \: { cm}^{2} = \frac{1}{2} \times 35 \times h \\ 840 \: {cm}^{2} = 35 \times h \\ h = 24 \: cm$

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Answer 2

Area of triangle is 1/2 *base*height (altitude)
Given =1/2*35*h=420cm
$h = 840 \div 35$
=24 cm