Question

A block placed on a horizontal surface is being
pushed by a force F making an angle theta with the
vertical if the friction coefficient is u, how
much force is needed to get the block just
started. Discuss the situation when tan theta < u.​

Full answer word to word

Answer 1

Answer:

Solution :

In limitting equilibrium force of friction `f = mu R`

In equilibrium along the horizontal `F sin theta = mu R`

and along the verticle `F cos theta + mg = R = (F sin theta )/(mu`

`:. Mg = F(( sin theta )/(mu) - cos theta)`

or `F = (mu mg)/(sin theta - mu cos theta)`

If tan `theta lt mu`

`(sin theta - mu cos theta lt theta)`

`:. F` is negative So for angles less angles less than `tan^(-1) mu` on cannot push the block ahed howsoever large the force may be .

Explanation:

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