Physics, asked by tubaabdulqadir, 4 months ago

A block weighing 20 N is lifted 6 m vertically upward. Calculate the potential energy stored in it.
1 3.33 J
2 124 J
3 72 J
4 120 J

Answers

Answered by BrainlyRonaldo
63

\bigstar Given

A block weighing 20 N is lifted 6 m vertically upward

\bigstar To Find

Potential energy stored in it

\bigstar Solution

We know that

\blue{\rm \longrightarrow F=m \times g}

\green{\rm \longrightarrow U=m \times g \times h}

Hence

\red{\rm \longrightarrow U=F \times h}

Here

  • U = Potential Energy
  • F = Force
  • h = Height

Units

  • U = Joule (J)
  • F = Newton (N)
  • h = metre (m)

According to the question

We are asked to find potential energy stored in it

Therefore

We must find "U"

Given that

A block weighing 20 N is lifted 6 m vertically upward

Hence

  • F = 20 N
  • h = 6 m

Substituting the values

We get

\orange{\rm \longrightarrow U=20 \times 6 \ J}

Therefore

\pink{\rm \longrightarrow U=120 \ J}

Hence

Potential energy stored in it = 120 J

Therefore

\checkmark Option (4) is correct

Answered by DARLO20
85

\Large\bf{\color{indigo}GiVeN,} \\

  • Weight of a block is 20N.

  • The block is lifted 6m vertically upward.

\Large\bf{\color{cyan}To\:FiNd,} \\

  • The potential energy stored in the block.

\Large\bf{\color{coral}CaLcUlAtIoN,} \\

Weight Of A Body ;-

  • The force exerted on a body by gravity, is known as Weight of a body.

The expression of weight of a body is

\orange\bigstar\:\:\bf{\color{olive}Weight\:(W)\:=\:mg\:}--(1) \\

\bf\pink{Where,} \\

  • m = mass of a body

  • g = gravitational acceleration

\bf\red{We\:know\:that,} \\

\green\bigstar\:\:\bf\blue{Potential\:Energy\:=\:mgh\:} \\

\bf\pink{Where,} \\

  • h = Height

➡ From equation(1) using the expression of weight in the above equation

:\implies\:\:\bf{Potential\:Energy\:=\:Weight\times{Height}\:} \\

:\implies\:\:\bf{Potential\:Energy\:=\:20\:N\times{6\:m}\:} \\

:\implies\:\:\bf{Potential\:Energy\:=\:120\:N.m\:} \\

:\implies\:\:\bf\purple{Potential\:Energy\:=\:120\:J\:} \\

\Large\bold\therefore The potential energy stored in the block is 120 J.

\red\bigstar\:\:{\boxed{\boxed{\green{\bf{Correct\:Option\:\longrightarrow\:(4)\:120\:J\:}}}}}

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