Question

A block with lenght of p = 2 m, width l = 2 m, height t = 0.5 m and mass m = 600 kg lays on the table. What is the pressure at the bottom surface of the block?

Answer 1

Given:

• Mass of block,m = 600 kg

• Acceleration due to gravity , g = 9.8 m/s²

• Length = 2m

• Breadth = 2 m

• Height = 0.5 m

To be calculated:

Calculate the pressure at the bottom surface of the block?

Solution:

Weight of block = m × g

= 600 × 9.8

= 60 × 98

= 5880 N

Weight = Force = 5880 N

Now,

Bottom Surface Area = 2m × 2m

= 4m²

Pressure = Force/Area

★ Substituting the values of force and area, we get

Pressure = 5880 / 4

= 1470 N/m²

= 1470 Pa

Thus, the pressure exerted by block is 1470 Pascal .

Answer 2

$\huge{\underline{\pink{\tt{Given,}}}}$

• Mass of Block = 600 kg
• Length = 2m
• Breadth = 2m
• Height = 0.5m
• Acceleration Due to Gravity = 9.8 m/s²

$\huge{\underline{\pink{\tt{To \ Find,}}}}$

• The Pressure at the bottom surface of the Block

$\huge{\underline{\pink{\tt{Solution :}}}}$

$\longrightarrow$We know that :

$\bigstar \boxed{\sf{Pressure = \dfrac{Force}{Area}}}$

║From this Formula We Find Force Firstly :  ║

$\therefore \boxed{\sf{Force = Pressure \times Area}}$

Therefore, We know that :

$\mapsto \underline{\boxed{\sf{Force = Weight = m \times g}}}$

Now We Find Force,

$\implies \sf{Force = m \times g}$

$\implies \sf{Force = 600 \times 9.8}$

$\implies \boxed{\sf{Force = 5880N}}$

Now We Find Area,

$\bigstar \boxed{\sf{Area = Length \times Breadth}}$

$\implies \sf{Area = 2 \times 2}$

$\implies \boxed{\sf{Area = 4 m^{2}}}$

Therefore, Now We have Both Area And Force

$\implies \sf{Pressure = \dfrac{Force}{Area}}$

$\implies \sf{Pressure = \dfrac{5880}{4}}$

$\implies \boxed{\sf{Pressure = 1470\: N/m^{2} or\:Pascal}}$(Answer)

$\rule{200}2$