A blocks of mass m is pulled on a rough horizontal surface which has a friction coefficient mew. A horizontal for F is applied which is capable of moving the body uniformly with speed v. Find the work done on the block in timet by (a) weight of the block, (b) Normal reaction by surface on the block, (c) friction, (d) F.
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Explanation:
Work of weight = work of normal = 0 because the direction of the force is perpendicular to the displacement. Work of F = Fvt because angle between applied force and displacement is 0 and work of friction = - (mew)mgvt because angle is 180 in degrees
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