A blub rated 36w 12v is connected to 20v cell. Find the resistance required to glow it with full intensity
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Its effective resistance at the rated voltage would be from P = E²/R. So R = E²/P = 144/36 = 4Ω. Current is E/R = 12/4 = 3A. Now you need to drop 8 volts at 3 amps. R = E/I = 8/3 = 2.7Ω.
Just to check - total resistance is 2.7 + 4 = 6.7 ohms. Total voltage 20 V so current is 3 amps. Power in lamp with 12 volts and 3 amps = 12 × 3 = 36 W
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