A boat covers 32 km upstream and 36 km downstream in 7 hrs,also it covers 40km upstream and 48 km downstream in 9hrs.Find the speed of boat in still water and that of the stream
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hey friend...
let the speed of boat in still water is x km/hr
and the speed in stream is y km/hr.
so the speed in upstream is (x-y) km/hr and
downstream is (x+y) km/hr.
so the first eq. will be
32/(x-y) + 36/(x+y) = 7
and the other will be
40/(x-y) + 48/(x+y)=9
so let 1/(x-y) be u and 1/(x+y) be v
so the current eq will be
30u+36v=7
40u+48v=9
so by applying the elimination method u will get the value of u.
then by putting u in given eq you will get the value of v.
so by the u&v you will get (x-y) and (x+y)
so after that you will get the speed in still water and in stream ..
hope it will help you.....
let the speed of boat in still water is x km/hr
and the speed in stream is y km/hr.
so the speed in upstream is (x-y) km/hr and
downstream is (x+y) km/hr.
so the first eq. will be
32/(x-y) + 36/(x+y) = 7
and the other will be
40/(x-y) + 48/(x+y)=9
so let 1/(x-y) be u and 1/(x+y) be v
so the current eq will be
30u+36v=7
40u+48v=9
so by applying the elimination method u will get the value of u.
then by putting u in given eq you will get the value of v.
so by the u&v you will get (x-y) and (x+y)
so after that you will get the speed in still water and in stream ..
hope it will help you.....
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