Math, asked by somireddygkr, 1 year ago

A boat goes 11km an hour in still water but takes four times as much time in going the same distance against the current. The speed of the current is

Answers

Answered by ishabatra21
1

Hi there!!!

.

Let the velocity of the boat be v km/h and velocity of the current be u km/h. 


When the boat goes in still water, its velocity is v=6 km/h. 


When the boat goes against the current, its velocity is v-u=(6-u) km/h. 


For distance S, time taken in still water to cover the distance = S/6 hous 


For same distance S, time taken while going against the current = S/(6-u) hours. 


According to given, S/(6-u) = 3*(S/6) 


=> 1/(6-u) = 1/2 

=> 6-u = 2 

=> u=4 km/h. 


So, the speed of the current is 4 km/h.

.

Hope it helps


somireddygkr: answer is 8.25
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