A boat having a length 3 m and breadth 2 m is floating on water the boat sinks by I cm, when a man gets on it .What is the mass of the man ?
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Volume of water displaced = (3 x 2 x 0.01) m3 [1cm =0.01 meter]
= 0.06 m3.
Mass of man = Volume of water displaced x Density of water
= (0.06 x 1000) kg
= 60 kg.
= 0.06 m3.
Mass of man = Volume of water displaced x Density of water
= (0.06 x 1000) kg
= 60 kg.
Answered by
3
We use the Archimedes law.
The additional volume of water displaced by the boat when the man gets onto it,
= 3 m * 2 m * 1 cm = 0.06 m³
So the weight of the man = weight of 0.06 m³ of water
= 0.06 m³ * 1000 kg/m³
= 60 kg
The additional volume of water displaced by the boat when the man gets onto it,
= 3 m * 2 m * 1 cm = 0.06 m³
So the weight of the man = weight of 0.06 m³ of water
= 0.06 m³ * 1000 kg/m³
= 60 kg
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