Question

A boat is moving towards east with velocity 4 m/s with resoect tostill water and river is flowing towards north with 2m/s and wind is blowing towards north with 6m/s. The direction of the flag blown over by the wind hoisted on the boat is

Answer 1

Let us assume +ve X-axis is towards East and +ve Y-axis is towards North.

Boat velocity = 4 m/s towards east = 4i ;

velocity of river = 2 m/s towards North = 2j ;

velocity of wind = 6 m/s towards North = 6J ;

sum of all velocity vectors = 4 i + 8 j

direction of this vector 4 i + 8 j is tan-1 (8/4) = 63º with X-axis

Hence direction of flag blown is 27º East of North