A boat takes 25 hours for travelling
downstream from point A to point B and
coming back to point C midway between A
and B. If the velocity of the stream is 5 km/hr
and the speed of the boat in still water is 10
km/hr, what is the distance between A and B?
Answers
Answer:
Let the distance between A & B be 2X km
Time taken to go from A to B downstream = 2X / (10+5) = 2X/15 hours
Time taken to go upstream from B to C = X/ (10–5) = X/5 hours
Total Time = 2X/15 + X/5 = 25
MULTIPLY BOTH SIDES OF EQUATION BY 15
2X +3X = 375
5X = 375
X = 75
2X = 150 km ANSWER
CHECK
150 / (10+5) = 150/15 = 10 hours
75 / (10–5) = 75/5 = 15 hours
ADD =25 hours
Step-by-step explanation:
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Answer:
Upstream means to move against the direction of the flowing water body while downstream means to move exactly opposite to the previously described direction.
Next, we look into the parameters given and they are, time, distance, and velocity(Speed).
Time (T) = distance (d) ÷ Speed (V)
Let the distance between A and B be 2X and between B and C is X
Let the Times taken from A to B and from B to C be t1 and t2 respectively.
Relative speed upstream from A to B = 10kmph - 5kmph = 5kmph.
Relative speed downstream from B to C = 10kmph + 5kmph = 15kmph.
T = t1 + t2 = 25h
(2X | 15) + (X | 5) = 25
Multiplying both sides of the equal sign by the l.c.m which is 15, we have,
2X + 3X = 15 * 25
Therefore, X = 75km
Implying that the distance between A and B which is 2X is 150km.