a boat was steered over a flowing river in such a way that it reached the opposite bank following the shortest path.time required in this case was double the time the boat would have taken to cross the river if there was no river current.if the velocity of the boat is 2 m/s.what was the velocity of the current?
Answers
Answered by
5
Answer:
sinθ=105=21∴θ=30∘∴anglewithriverflow=120∘.
hence, the options A is the correct answer.

Answered by
4
Answer:√3 m.s^-1
Explanation:
We know that the time required to cross the river in shortest distance is t=l/√[v²-u²]
Again according to the question
l/v ( time required to cover the distance when there is no current
So by the problem
2×l/v=l/√[v²-u²]
or 4/v²=l/v²-u²
or v²/4=v²-u²
or u²=3v²/4
or u²=3×4/4. (By the question v= 2)
or u=√3 (ans)
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