. A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water ?
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Here is your answer dear friend,
============================
let the speed of current is= (y)
let the speed of boat is = (x)
ATQ. case1
2km/1hour = (x-y)
x-y = 2------------------(1)
ATQ. case2
1km/1/6hours. = (x+y)
x+y = 6----------------(2)
By eliminating (1) & (2)
-2y = -4
y = 4/2
y = 2
x=2+4---------(from(1).)
x = 6
So, the boat will take time to go 5km in stationary water is
Distance/speed =Time
5/6 = time
Time = 0.8333....hours
=========================
Hope this will help you and please mark as brainlist answer and follow for such more solutions.
============================
let the speed of current is= (y)
let the speed of boat is = (x)
ATQ. case1
2km/1hour = (x-y)
x-y = 2------------------(1)
ATQ. case2
1km/1/6hours. = (x+y)
x+y = 6----------------(2)
By eliminating (1) & (2)
-2y = -4
y = 4/2
y = 2
x=2+4---------(from(1).)
x = 6
So, the boat will take time to go 5km in stationary water is
Distance/speed =Time
5/6 = time
Time = 0.8333....hours
=========================
Hope this will help you and please mark as brainlist answer and follow for such more solutions.
kamalmahipal:
ruk
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