Question

a body 72 n move from the surface of earth at at height 1/2 of the earth radius the gravitational force exerted on it

Answer 1

first answer in image after image continue this bellow written text answer

i.e. we get
gh = 4/9 g
So acceleration due to gravity at a height R/2 above the surface of the earth is 4/9 times to that on the surface of the earth
So weight at that height will be
Wh = m(4/9g) = 4/9 mg
i.e.
Wh = 4/9 W
So weight will be 4/9 times weight at the surface of the earth
We are given weight on the surface of the earth as
W = 63 N, so we have
Wh = 4/9 × 63N = 28 N
So the weight of the body or gravitational force on it due to the earth at a height equal to half the radius of the earth will be 28 N


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