Question

A body A starts from rest and accelerates at constant rate x for time t. Another body B moves with constant speed x for the time t. Compare the displacement if A and B

Answer 1

Answer:

actually both have no delta in their respective displacement beacuse as one is moving with constant velocity and constant accleration other is so no delta will be there hope it will help you

Answer 2

The displacement of A is t/2 times the displacement of B

Explanation:

For body A

Initial velocity $u_A=0$

Acceleration $a_A=x$

In time t the displacement of the body A

By the second equation of motion

$s_A=u_At+\frac{1}{2}a_At^2$

$\implies s_A=0+\frac{1}{2}\times x\times t^2$

$\implies s_A=\frac{xt^2}{2}$

Body B  moves with constant speed x for the time t.

Therefore, the displacement of body B in time t

$s_B=x\times t$

$\implies s_B=xt$

$\frac{s_A}{s_B}=\frac{xt^2/2}{xt}$

$\implies \frac{s_A}{s_B}=\frac{t}{2}$

$\implies s_A=s_B\times \frac{t}{2}$

Therefore, the displacement of A is t/2 times the displacement of B

Hope this answer is helpful.

Know More:

Q: A particle starting from rest moves with constant acceleration. If it takes 5.0 s to reach the speed 18 km/h find (a) the average velocity during this period , and (b) the distance traveled by the particle during this period

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