Physics, asked by Kaurd, 1 year ago

A body accelerates from 5m/s to15m/s in 10s.calculate the acceleration and the distance covered by the car during this time interval

Answers

Answered by parisakura98pari
27
initial velocity of body = u = 5 m/s
final velocity f body =  v = 15 m/s
time taken = t =10 s

now acceleration of body is the change in velocity per unit time
 = a = v-u/t = 15-5/10 = 10/10 = 1 m/s²

distance covered = s= ut + at²/2 = 5(10) + 1 (10)(10)/2 = 100m

hope my answer is correct.

Answered by MridulAhi1234
22
u = 5 m/s
v = 15m/s
t = 10 seconds
v = u + at
15 = 5 + 10a
10a = 15-5
a= 10/10
a = 1 m/s²
s = ut + 1/2at²
= 5×10 + 1/2×1×100
= 50+50
= 100m

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