Question

a body accelerates uniformly from rest to 20 m/s for 4 sec, then moves with same velocity for the next 6 sec, after this it retards to come to rest in 2 sec.
(a) Draw velocity-time graph for the motion and form it.
(b) Find the total distance covered by the body.

please answer it fast !!! I want it now !!!

Answer 1

The total distance is the area under the graph. The area under the graph is a trapezium

We therefore use the formulae of getting the area of a trapezium.

(a+b) /2 ×h

h=20

a=6
b=12

A=(6+12)/2 ×20=180m

180m.

The image gives the graph of the motion.

Answer 2

Answer:

your answer is 180 m

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