a body accelerates uniformly from rest to 20 m/s for 4 sec, then moves with same velocity for the next 6 sec, after this it retards to come to rest in 2 sec.
(a) Draw velocity-time graph for the motion and form it.
(b) Find the total distance covered by the body.
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The image below contains the graph of the motion of the body.
The area under the graph gives the distance.
The area is a trapezium.
Formulae for getting area of a trapezium :
(a+b) /2 × h
a=6s
b=12s
h=20m/s
A=(6+12)/2 ×20
9×20=180m
180m
The area under the graph gives the distance.
The area is a trapezium.
Formulae for getting area of a trapezium :
(a+b) /2 × h
a=6s
b=12s
h=20m/s
A=(6+12)/2 ×20
9×20=180m
180m
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