a body at rest has mass 10 kg is moved by horizontal force of 5 Newton on a horizontal surface then the work done by the force in 8 seconds is
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Answered by
14
workdone = mdcos€
than,
mass- 10 kg
force- 5 N
hence, work done- 5×10cos 0°
- 50 kgN.
- 50 joule.(ans)
than,
mass- 10 kg
force- 5 N
hence, work done- 5×10cos 0°
- 50 kgN.
- 50 joule.(ans)
madhavan2006:
wrongggg
Answered by
42
force=m(v-u)/t
5=10(v-0)/8
5/10×8=v
4=v
a=(v-u)/t
a=4-0/8
a=4/8
a=1/2
s=ut+1/2at^2
s=0×8+1/2×1/2×8×8
s=16
work=force×displacement
work=5×16
work done=80
5=10(v-0)/8
5/10×8=v
4=v
a=(v-u)/t
a=4-0/8
a=4/8
a=1/2
s=ut+1/2at^2
s=0×8+1/2×1/2×8×8
s=16
work=force×displacement
work=5×16
work done=80
wronggggg
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