Question

A body builder exerts a force of 150 N against a bullworker and compresses it by 20 cm. Calculate the spring constant of the spring in the bullworker.
Concept of Physics - 1 , HC VERMA , Chapter "The Force".

Answer 1

Hello Dear.

Here in the question it is given that :- 

The body builder exert a force and its compression

Force F = 150 N  ; x = 20 cm = 0.2 m 
We know that ,
F = kx
where F is the applied force ,  k is the spring constant and x is the deflection of spring. 
Now from the formula ,we get
k= F/x

k= 150/0.2
k= 750 N/m . 

Hence the spring constant of the spring in the bullworker is 750 N/m . 


Hope it Helps.

Answer 2

HEY!!

____________________________

✴Force exerted by the body builder against the bullworker = 150 N

⚫Compression in the bullworker, x =20 cm=0.2m

✔Total force exerted, f = kx = 150

⚫Here, k is the spring constant of the spring in the bullworker.

✔k=150/0.2=1500/2=750 N/m

▶▶Hence, the spring constant of the spring in the bullworker is 750 N/m.