Question

A body cools in 10 minutes from 60^@C to 40^@C. What will be its temperature after next 10 minutes? The temperature of the surroundings is 10^@C.

Answer 1

The temperature of the body after 10 minutes will be 28^@C

• Let us first go through the given parameters in the question
• Temperatures : T1=60^@C

                            T2=40^@C

                            T=10^@C

                            T3=?

• Time periods   :  t1 = 10 min

                            t2 = 10 min

• From NEWTON’S LAWS OF COOLING we have the formula

           (T1-T2)/t = c [(T1+T2)/2-T]

             Where  c is constant

                           T be the surrounding temperature

• By substituting the above values in this equation

           (60-40)/10= c [(60+40)/2-10]……………(1)

           (40-T3)/10= c [(40+T3)/2-10]……………(2)

• By Solving the above two equations the value of T3 can  be determined

• The Temperature of body after 10 mins will be T3=28^@C