Physics, asked by vaibhavikavin, 1 year ago

A body covered a distance of x meter along a semicircular path.Calculate the magnitude of displacement of the body,and the ratio of distance to displacement?

Answers

Answered by Haezel
75

Answer:

The magnitude of displacement is  2 [A/ π]  and ratio of distance to displacement is π : 2

Explanation:

Consider r as the radius of semicircular path.  

When a body covers distance of x meter along a circular path, distance covered by body will be 2π r. But here body is covering distance along semicircular path. So distance covered by body will be π r.

Now Let’s find the displacement of the body.

Distance covered by body, A = π r   ------(1)

Displacement = Diameter of the semicircular path = 2r ----- (2)

Putting the value of r from equation (1) to equation (2),  

Displacement = 2 [A/ π]

Ratio of distance to displacement = A : 2A/ π = π : 2

Answered by singhvaishnavi56260
33

Hi buddy

there's your answer in the picture with the solution

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