A body covered a distance of x meter along a semicircular path.Calculate the magnitude of displacement of the body,and the ratio of distance to displacement?
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Answered by
75
Answer:
The magnitude of displacement is 2 [A/ π] and ratio of distance to displacement is π : 2
Explanation:
Consider r as the radius of semicircular path.
When a body covers distance of x meter along a circular path, distance covered by body will be 2π r. But here body is covering distance along semicircular path. So distance covered by body will be π r.
Now Let’s find the displacement of the body.
Distance covered by body, A = π r ------(1)
Displacement = Diameter of the semicircular path = 2r ----- (2)
Putting the value of r from equation (1) to equation (2),
Displacement = 2 [A/ π]
Ratio of distance to displacement = A : 2A/ π = π : 2
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33
Hi buddy
there's your answer in the picture with the solution
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