Question

A body covers 12min 2ndsecondand20min4thsecond.Howmuchdistancewillitcoverin4secondsafter the 5th second

Answer 1

Explanation:

S=u+a/2(2n+1).....n=no of second

Answer 2

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s=u+a(2t−1)/2

12 = u + a(2*2 - 1)/2

=> 12 = u + 3a/2

=> 2u + 3a = 24

and

20 = u + a(2*4 - 1)/2

20 = u + 7a/2

=> 2u + 7a = 40

From 1 and 2:

a = 4

u = 6

Now, distance covered in 4s after 5th second = Distance covered in 9 seconds - distance covered in 5 seconds

= 6*9 + 1/2 * 4 * 9 * 9 - (6 * 5 + 1/2 * 4 * 5 * 5)

= 54 + 162 - (30 + 50)

= 136 m