a body covers a distance of 2km at a speed of 5km/h while going to market from his home he comes back home covering the same distance at a speed of 4km/h calculate the time taken in hour as well as seconds. plzzz friends help me
Answers
distance is 2 km and speed is 5 km/h. then time T1 = distance/speed , T1 = 2/5 , T1= 0.4 hr, and then return back with speed 4 km/h then Time T2= 2/4 , T2= 0.5 hr and whole time is T1+T2, 0.4+0.5=T ,T= 0.9 hr and in sec 0.9×60×60=3240 sec
A body covers a distance of 2 km at a speed of 5 km/hr while going from his home and then returns back to his home using the same pathway with a speed of 4 km/hr.
We have to find the time taken by the body in hours and seconds.
Total distance covered by body = Distance covered from home to market + Distance covered from market to home
= (2 + 2) km
= 4 km
Now,
Time = Distance/Speed
For Case 1) i.e. from home to market:
t1 = 2/5 hr.
For Case 1) i.e. from market to home:
t2 = 2/4 hr.
Total time taken by body = t1 + t2
= 2/5 + 2/4
= (8 + 10)/20
= 18/20
= 0.9 hours
Therefore, the time taken by the body is 0.9 hours.
In seconds:
From above calculations time taken by the body is 0.9 hours. To convert hours into seconds. Multiply the given value by 3600.
Time = 0.9 × 3600 = 3240 sec
Therefore, the time taken by the body is 3240 seconds.