Physics, asked by TrapNation, 1 year ago

A body covers a distance of 5m along a semicircular path. The ratio of distance to displacement is ??


TrapNation: Yup dude

Answers

Answered by deepakbansal19paywop
10

It travels semicircular path


Distance = πr

5 = πr

r = 5/π


Displacement = Distance between initial position and final position

= 2r

= 2 * 5/π

= 10/π metres


Ratio of distance to displacement

= 5 / (10 / π)

= π/2

= 11/7

= 11 : 7



Answered by vaibhavshinde145
4

It travels semicircular path

Distance = πr

5 = πr

r = 5/π

Displacement = Distance between initial position and final position

= 2r

= 2 * 5/π

= 10/π metres

Ratio of distance to displacement

= 5 / (10 / π)

= π/2

= 11/7

= 11 : 7

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