A body covers a distance of 5m along a semicircular path. The ratio of distance to displacement is ??
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Answers
Answered by
10
It travels semicircular path
Distance = πr
5 = πr
r = 5/π
Displacement = Distance between initial position and final position
= 2r
= 2 * 5/π
= 10/π metres
Ratio of distance to displacement
= 5 / (10 / π)
= π/2
= 11/7
= 11 : 7
Answered by
4
It travels semicircular path
Distance = πr
5 = πr
r = 5/π
Displacement = Distance between initial position and final position
= 2r
= 2 * 5/π
= 10/π metres
Ratio of distance to displacement
= 5 / (10 / π)
= π/2
= 11/7
= 11 : 7
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