Question

A body describes a semi circular path of radius 7m in 11s.Find the speed and magnitude of velocity of the body​

Answer 1

Answer:

speed will be equal to distance by time it means

speed=7m/11sec which is equal to 7/11 meter per second

Answer 2

The speed and magnitude of velocity of the body​ is 2 m/s and 1.28 m/s respectively.

Explanation:

Given that,

Radius of a semicircular path, r = 7 m

Time, t = 11 s

The distance traveled by a body in circular path is given by :

$d=\pi r$

The speed of a body is given by :

$s=\dfrac{\pi r}{t}\\\\s=\dfrac{\pi \times 7}{11}\\\\s=1.99\ m/s\\\\\text{or}\\\\s=2\ m/s$

The displacement divided by time is called velocity of the body. It is also known as the shortest path covered.

Here, displacement is,

$D=2r\\\\D=2\times 7=14\ m$

$v=\dfrac{14}{11}\\\\v=1.28\ m/s$

So, the speed and magnitude of velocity of the body​ is 2 m/s and 1.28 m/s respectively.

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